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x^{2}=4+3^{2}-2\times 3\times 2+\frac{1}{3}
Calculate 2 to the power of 2 and get 4.
x^{2}=4+9-2\times 3\times 2+\frac{1}{3}
Calculate 3 to the power of 2 and get 9.
x^{2}=13-2\times 3\times 2+\frac{1}{3}
Add 4 and 9 to get 13.
x^{2}=13-6\times 2+\frac{1}{3}
Multiply 2 and 3 to get 6.
x^{2}=13-12+\frac{1}{3}
Multiply 6 and 2 to get 12.
x^{2}=1+\frac{1}{3}
Subtract 12 from 13 to get 1.
x^{2}=\frac{4}{3}
Add 1 and \frac{1}{3} to get \frac{4}{3}.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
Take the square root of both sides of the equation.
x^{2}=4+3^{2}-2\times 3\times 2+\frac{1}{3}
Calculate 2 to the power of 2 and get 4.
x^{2}=4+9-2\times 3\times 2+\frac{1}{3}
Calculate 3 to the power of 2 and get 9.
x^{2}=13-2\times 3\times 2+\frac{1}{3}
Add 4 and 9 to get 13.
x^{2}=13-6\times 2+\frac{1}{3}
Multiply 2 and 3 to get 6.
x^{2}=13-12+\frac{1}{3}
Multiply 6 and 2 to get 12.
x^{2}=1+\frac{1}{3}
Subtract 12 from 13 to get 1.
x^{2}=\frac{4}{3}
Add 1 and \frac{1}{3} to get \frac{4}{3}.
x^{2}-\frac{4}{3}=0
Subtract \frac{4}{3} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{4}{3}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{4}{3} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{4}{3}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{16}{3}}}{2}
Multiply -4 times -\frac{4}{3}.
x=\frac{0±\frac{4\sqrt{3}}{3}}{2}
Take the square root of \frac{16}{3}.
x=\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±\frac{4\sqrt{3}}{3}}{2} when ± is plus.
x=-\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±\frac{4\sqrt{3}}{3}}{2} when ± is minus.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
The equation is now solved.