Solve x^2=14^2+14^2

$$x ^ { 2 } = 14 ^ { 2 } + 14 ^ { 2 }$$

Solve for x

$$x=14\sqrt{2}\approx 19.798989873$$

$$x=-14\sqrt{2}\approx -19.798989873$$

Steps by Finding Square Root

Calculate 14 to the power of 2 and get 196.

$$x^{2}=196+14^{2}$$

Calculate 14 to the power of 2 and get 196.

$$x^{2}=196+196$$

Add 196 and 196 to get 392.

$$x^{2}=392$$

Take the square root of both sides of the equation.

$$x=14\sqrt{2} x=-14\sqrt{2}$$

Steps Using the Quadratic Formula

Calculate 14 to the power of 2 and get 196.

$$x^{2}=196+14^{2}$$

Calculate 14 to the power of 2 and get 196.

$$x^{2}=196+196$$

Add 196 and 196 to get 392.

$$x^{2}=392$$

Subtract 392 from both sides.

$$x^{2}-392=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -392 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-392\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-392\right)}}{2}$$

Multiply -4 times -392.

$$x=\frac{0±\sqrt{1568}}{2}$$

Take the square root of 1568.

$$x=\frac{0±28\sqrt{2}}{2}$$

Now solve the equation x=\frac{0±28\sqrt{2}}{2} when ± is plus.

$$x=14\sqrt{2}$$

Now solve the equation x=\frac{0±28\sqrt{2}}{2} when ± is minus.

$$x=-14\sqrt{2}$$

The equation is now solved.

$$x=14\sqrt{2} x=-14\sqrt{2}$$