Solve x^2=12^3-sqrt{4}

$$x ^ { 2 } = 12 ^ { 3 } - \sqrt { 4 }$$

Solve for x

$$x=\sqrt{1726}\approx 41.545156156$$

$$x=-\sqrt{1726}\approx -41.545156156$$

Steps by Finding Square Root

Calculate 12 to the power of 3 and get 1728.

$$x^{2}=1728-\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$x^{2}=1728-2$$

Subtract 2 from 1728 to get 1726.

$$x^{2}=1726$$

Take the square root of both sides of the equation.

$$x=\sqrt{1726} x=-\sqrt{1726}$$

Steps Using the Quadratic Formula

Calculate 12 to the power of 3 and get 1728.

$$x^{2}=1728-\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$x^{2}=1728-2$$

Subtract 2 from 1728 to get 1726.

$$x^{2}=1726$$

Subtract 1726 from both sides.

$$x^{2}-1726=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -1726 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1726\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-1726\right)}}{2}$$

Multiply -4 times -1726.

$$x=\frac{0±\sqrt{6904}}{2}$$

Take the square root of 6904.

$$x=\frac{0±2\sqrt{1726}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{1726}}{2} when ± is plus.

$$x=\sqrt{1726}$$

Now solve the equation x=\frac{0±2\sqrt{1726}}{2} when ± is minus.

$$x=-\sqrt{1726}$$

The equation is now solved.

$$x=\sqrt{1726} x=-\sqrt{1726}$$