Solve x^2=1.62

$$x ^ { 2 } = 1.62$$

Solve for x

$$x = \frac{9 \sqrt{2}}{10} \approx 1.272792206$$

$$x = -\frac{9 \sqrt{2}}{10} \approx -1.272792206$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\frac{9\sqrt{2}}{10} x=-\frac{9\sqrt{2}}{10}$$

Steps Using the Quadratic Formula

Subtract 1.62 from both sides.

$$x^{2}-1.62=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -1.62 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1.62\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-1.62\right)}}{2}$$

Multiply -4 times -1.62.

$$x=\frac{0±\sqrt{6.48}}{2}$$

Take the square root of 6.48.

$$x=\frac{0±\frac{9\sqrt{2}}{5}}{2}$$

Now solve the equation x=\frac{0±\frac{9\sqrt{2}}{5}}{2} when ± is plus.

$$x=\frac{9\sqrt{2}}{10}$$

Now solve the equation x=\frac{0±\frac{9\sqrt{2}}{5}}{2} when ± is minus.

$$x=-\frac{9\sqrt{2}}{10}$$

The equation is now solved.

$$x=\frac{9\sqrt{2}}{10} x=-\frac{9\sqrt{2}}{10}$$