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x^{2}=1+4-4x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-x\right)^{2}.
x^{2}=5-4x+x^{2}
Add 1 and 4 to get 5.
x^{2}+4x=5+x^{2}
Add 4x to both sides.
x^{2}+4x-x^{2}=5
Subtract x^{2} from both sides.
4x=5
Combine x^{2} and -x^{2} to get 0.
x=\frac{5}{4}
Divide both sides by 4.