Solve x^2+yx+18=0

$$x ^ { 2 } + y x + 18 = 0$$

Solve for y

$$y=-x-\frac{18}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$yx+18=-x^{2}$$

Subtract 18 from both sides.

$$yx=-x^{2}-18$$

The equation is in standard form.

$$xy=-x^{2}-18$$

Divide both sides by x.

$$\frac{xy}{x}=\frac{-x^{2}-18}{x}$$

Dividing by x undoes the multiplication by x.

$$y=\frac{-x^{2}-18}{x}$$

Divide -x^{2}-18 by x.

$$y=-x-\frac{18}{x}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{y^{2}-72}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-72}-y}{2}$$

Solve for x

$$x=\frac{\sqrt{y^{2}-72}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-72}-y}{2}\text{, }|y|\geq 6\sqrt{2}$$