Solve x^2+y^2-2dx=0

$$x ^ { 2 } + y ^ { 2 } - 2 d x = 0$$

Solve for d (complex solution)

$$\left\{\begin{matrix}d=\frac{x^{2}+y^{2}}{2x}\text{, }&x\neq 0\\d\in \mathrm{C}\text{, }&x=0\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$y^{2}-2dx=-x^{2}$$

Subtract y^{2} from both sides.

$$-2dx=-x^{2}-y^{2}$$

The equation is in standard form.

$$\left(-2x\right)d=-x^{2}-y^{2}$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)d}{-2x}=\frac{-x^{2}-y^{2}}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$d=\frac{-x^{2}-y^{2}}{-2x}$$

Divide -x^{2}-y^{2} by -2x.

$$d=\frac{y^{2}}{2x}+\frac{x}{2}$$

Solve for d

$$\left\{\begin{matrix}d=\frac{x^{2}+y^{2}}{2x}\text{, }&x\neq 0\\d\in \mathrm{R}\text{, }&x=0\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$y^{2}-2dx=-x^{2}$$

Subtract y^{2} from both sides.

$$-2dx=-x^{2}-y^{2}$$

The equation is in standard form.

$$\left(-2x\right)d=-x^{2}-y^{2}$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)d}{-2x}=\frac{-x^{2}-y^{2}}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$d=\frac{-x^{2}-y^{2}}{-2x}$$

Divide -x^{2}-y^{2} by -2x.

$$d=\frac{y^{2}}{2x}+\frac{x}{2}$$

Solve for x (complex solution)

$$x=\sqrt{d^{2}-y^{2}}+d$$

$$x=-\sqrt{d^{2}-y^{2}}+d$$

Solve for x

$$x=\sqrt{d^{2}-y^{2}}+d$$

$$x=-\sqrt{d^{2}-y^{2}}+d\text{, }|y|\leq |d|$$