Solve x^2+y=3x*2y

$$x ^ { 2 } + y = 3 x \times 2 y$$

Solve for y

$$y=-\frac{x^{2}}{1-6x}$$

$$x\neq \frac{1}{6}$$

Steps for Solving Linear Equation

Multiply 3 and 2 to get 6.

$$x^{2}+y=6xy$$

Subtract 6xy from both sides.

$$x^{2}+y-6xy=0$$

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$y-6xy=-x^{2}$$

Combine all terms containing y.

$$\left(1-6x\right)y=-x^{2}$$

Divide both sides by 1-6x.

$$\frac{\left(1-6x\right)y}{1-6x}=-\frac{x^{2}}{1-6x}$$

Dividing by 1-6x undoes the multiplication by 1-6x.

$$y=-\frac{x^{2}}{1-6x}$$

Solve for x (complex solution)

$$x=\sqrt{y\left(9y-1\right)}+3y$$

$$x=-\sqrt{y\left(9y-1\right)}+3y$$

Solve for x

$$x=\sqrt{y\left(9y-1\right)}+3y$$

$$x=-\sqrt{y\left(9y-1\right)}+3y\text{, }y\geq \frac{1}{9}\text{ or }y\leq 0$$