Solve x^2+xy+xx+yz=2

$$x ^ { 2 } + x y + x x + y z = 2$$

Solve for y (complex solution)

$$\left\{\begin{matrix}y=-\frac{2\left(x^{2}-1\right)}{x+z}\text{, }&x\neq -z\\y\in \mathrm{C}\text{, }&\left(x=-1\text{ and }z=1\right)\text{ or }\left(x=1\text{ and }z=-1\right)\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$x^{2}+xy+x^{2}+yz=2$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}+xy+yz=2$$

Subtract 2x^{2} from both sides.

$$xy+yz=2-2x^{2}$$

Combine all terms containing y.

$$\left(x+z\right)y=2-2x^{2}$$

Divide both sides by x+z.

$$\frac{\left(x+z\right)y}{x+z}=\frac{2-2x^{2}}{x+z}$$

Dividing by x+z undoes the multiplication by x+z.

$$y=\frac{2-2x^{2}}{x+z}$$

Divide -2x^{2}+2 by x+z.

$$y=\frac{2\left(1-x^{2}\right)}{x+z}$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{2\left(x^{2}-1\right)}{x+z}\text{, }&x\neq -z\\y\in \mathrm{R}\text{, }&\left(x=-1\text{ and }z=1\right)\text{ or }\left(x=1\text{ and }z=-1\right)\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$x^{2}+xy+x^{2}+yz=2$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}+xy+yz=2$$

Subtract 2x^{2} from both sides.

$$xy+yz=2-2x^{2}$$

Combine all terms containing y.

$$\left(x+z\right)y=2-2x^{2}$$

Divide both sides by x+z.

$$\frac{\left(x+z\right)y}{x+z}=\frac{2-2x^{2}}{x+z}$$

Dividing by x+z undoes the multiplication by x+z.

$$y=\frac{2-2x^{2}}{x+z}$$

Divide -2x^{2}+2 by x+z.

$$y=\frac{2\left(1-x^{2}\right)}{x+z}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{y^{2}-8yz+16}-y}{4}$$

$$x=\frac{-\sqrt{y^{2}-8yz+16}-y}{4}$$

Solve for x

$$x=\frac{\sqrt{y^{2}-8yz+16}-y}{4}$$

$$x=\frac{-\sqrt{y^{2}-8yz+16}-y}{4}\text{, }y\geq 4\sqrt{z^{2}-1}+4z\text{ or }y\leq -4\sqrt{z^{2}-1}+4z\text{ or }|z|\leq 1$$