Solve x^2+x-56=(x+8)(x-1)

$$x ^ { 2 } + x - 56 = ( x + 8 ) ( x - 1 )$$

Solve for x

$$x=-8$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+8 by x-1 and combine like terms.

$$x^{2}+x-56=x^{2}+7x-8$$

Subtract x^{2} from both sides.

$$x^{2}+x-56-x^{2}=7x-8$$

Combine x^{2} and -x^{2} to get 0.

$$x-56=7x-8$$

Subtract 7x from both sides.

$$x-56-7x=-8$$

Combine x and -7x to get -6x.

$$-6x-56=-8$$

Add 56 to both sides.

$$-6x=-8+56$$

Add -8 and 56 to get 48.

$$-6x=48$$

Divide both sides by -6.

$$x=\frac{48}{-6}$$

Divide 48 by -6 to get -8.

$$x=-8$$