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x^{2}+762048x+16003008=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-762048±\sqrt{762048^{2}-4\times 16003008}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-762048±\sqrt{580717154304-4\times 16003008}}{2}
Square 762048.
x=\frac{-762048±\sqrt{580717154304-64012032}}{2}
Multiply -4 times 16003008.
x=\frac{-762048±\sqrt{580653142272}}{2}
Add 580717154304 to -64012032.
x=\frac{-762048±3024\sqrt{63497}}{2}
Take the square root of 580653142272.
x=\frac{3024\sqrt{63497}-762048}{2}
Now solve the equation x=\frac{-762048±3024\sqrt{63497}}{2} when ± is plus. Add -762048 to 3024\sqrt{63497}.
x=1512\sqrt{63497}-381024
Divide -762048+3024\sqrt{63497} by 2.
x=\frac{-3024\sqrt{63497}-762048}{2}
Now solve the equation x=\frac{-762048±3024\sqrt{63497}}{2} when ± is minus. Subtract 3024\sqrt{63497} from -762048.
x=-1512\sqrt{63497}-381024
Divide -762048-3024\sqrt{63497} by 2.
x^{2}+762048x+16003008=\left(x-\left(1512\sqrt{63497}-381024\right)\right)\left(x-\left(-1512\sqrt{63497}-381024\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -381024+1512\sqrt{63497} for x_{1} and -381024-1512\sqrt{63497} for x_{2}.
x ^ 2 +762048x +16003008 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -762048 rs = 16003008
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -381024 - u s = -381024 + u
Two numbers r and s sum up to -762048 exactly when the average of the two numbers is \frac{1}{2}*-762048 = -381024. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-381024 - u) (-381024 + u) = 16003008
To solve for unknown quantity u, substitute these in the product equation rs = 16003008
224142336 - u^2 = 16003008
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 16003008-224142336 = -208139328
Simplify the expression by subtracting 224142336 on both sides
u^2 = 208139328 u = \pm\sqrt{208139328} = \pm \sqrt{208139328}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-381024 - \sqrt{208139328} = -762026.999 s = -381024 + \sqrt{208139328} = -21.001
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.