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\left(x+3y-z\right)\left(x+3y+z\right)
Rewrite x^{2}+6xy+9y^{2}-z^{2} as \left(x+3y\right)^{2}-z^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).