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\left(3+x-10y\right)\left(3+x+10y\right)
Rewrite x^{2}+6x+9-100y^{2} as \left(3+x\right)^{2}-\left(10y\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(x-10y+3\right)\left(x+10y+3\right)
Reorder the terms.