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x^{2}+6x-16
Multiply and combine like terms.
a+b=6 ab=1\left(-16\right)=-16
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-16. To find a and b, set up a system to be solved.
-1,16 -2,8 -4,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -16.
-1+16=15 -2+8=6 -4+4=0
Calculate the sum for each pair.
a=-2 b=8
The solution is the pair that gives sum 6.
\left(x^{2}-2x\right)+\left(8x-16\right)
Rewrite x^{2}+6x-16 as \left(x^{2}-2x\right)+\left(8x-16\right).
x\left(x-2\right)+8\left(x-2\right)
Factor out x in the first and 8 in the second group.
\left(x-2\right)\left(x+8\right)
Factor out common term x-2 by using distributive property.
x^{2}+6x-16
Subtract 22 from 6 to get -16.