Solve x^2+6x+4y+9=0

$$x ^ { 2 } + 6 x + 4 y + 9 = 0$$

Solve for y

$$y=-\frac{\left(x+3\right)^{2}}{4}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$6x+4y+9=-x^{2}$$

Subtract 6x from both sides.

$$4y+9=-x^{2}-6x$$

Subtract 9 from both sides.

$$4y=-x^{2}-6x-9$$

Divide both sides by 4.

$$\frac{4y}{4}=-\frac{\left(x+3\right)^{2}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=-\frac{\left(x+3\right)^{2}}{4}$$

Solve for x (complex solution)

$$x=2\sqrt{-y}-3$$

$$x=-2\sqrt{-y}-3$$

Solve for x

$$x=2\sqrt{-y}-3$$

$$x=-2\sqrt{-y}-3\text{, }y\leq 0$$