Solve x^2+6x+16=7x-12

$$x ^ { 2 } + 6 x + 16 = 7 x - 12$$

Solve for x (complex solution)

$$x=\frac{1+\sqrt{111}i}{2}\approx 0.5+5.267826876i$$

$$x=\frac{-\sqrt{111}i+1}{2}\approx 0.5-5.267826876i$$

Steps Using the Quadratic Formula

Subtract 7x from both sides.

$$x^{2}+6x+16-7x=-12$$

Combine 6x and -7x to get -x.

$$x^{2}-x+16=-12$$

Add 12 to both sides.

$$x^{2}-x+16+12=0$$

Add 16 and 12 to get 28.

$$x^{2}-x+28=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and 28 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1-4\times 28}}{2}$$

Multiply -4 times 28.

$$x=\frac{-\left(-1\right)±\sqrt{1-112}}{2}$$

Add 1 to -112.

$$x=\frac{-\left(-1\right)±\sqrt{-111}}{2}$$

Take the square root of -111.

$$x=\frac{-\left(-1\right)±\sqrt{111}i}{2}$$

The opposite of -1 is 1.

$$x=\frac{1±\sqrt{111}i}{2}$$

Now solve the equation x=\frac{1±\sqrt{111}i}{2} when ± is plus. Add 1 to i\sqrt{111}.

$$x=\frac{1+\sqrt{111}i}{2}$$

Now solve the equation x=\frac{1±\sqrt{111}i}{2} when ± is minus. Subtract i\sqrt{111} from 1.

$$x=\frac{-\sqrt{111}i+1}{2}$$

The equation is now solved.

$$x=\frac{1+\sqrt{111}i}{2} x=\frac{-\sqrt{111}i+1}{2}$$

Steps for Completing the Square

Subtract 7x from both sides.

$$x^{2}+6x+16-7x=-12$$

Combine 6x and -7x to get -x.

$$x^{2}-x+16=-12$$

Subtract 16 from both sides.

$$x^{2}-x=-12-16$$

Subtract 16 from -12 to get -28.

$$x^{2}-x=-28$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-28+\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=-28+\frac{1}{4}$$

Add -28 to \frac{1}{4}.

$$x^{2}-x+\frac{1}{4}=-\frac{111}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=-\frac{111}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{111}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{\sqrt{111}i}{2} x-\frac{1}{2}=-\frac{\sqrt{111}i}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=\frac{1+\sqrt{111}i}{2} x=\frac{-\sqrt{111}i+1}{2}$$