Solve x^2+6=32

$$x ^ { 2 } + 6 = 32$$

Solve for x

$$x=\sqrt{26}\approx 5.099019514$$

$$x=-\sqrt{26}\approx -5.099019514$$

Steps by Finding Square Root

Subtract 6 from both sides.

$$x^{2}=32-6$$

Subtract 6 from 32 to get 26.

$$x^{2}=26$$

Take the square root of both sides of the equation.

$$x=\sqrt{26} x=-\sqrt{26}$$

Steps Using the Quadratic Formula

Subtract 32 from both sides.

$$x^{2}+6-32=0$$

Subtract 32 from 6 to get -26.

$$x^{2}-26=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -26 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-26\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-26\right)}}{2}$$

Multiply -4 times -26.

$$x=\frac{0±\sqrt{104}}{2}$$

Take the square root of 104.

$$x=\frac{0±2\sqrt{26}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{26}}{2} when ± is plus.

$$x=\sqrt{26}$$

Now solve the equation x=\frac{0±2\sqrt{26}}{2} when ± is minus.

$$x=-\sqrt{26}$$

The equation is now solved.

$$x=\sqrt{26} x=-\sqrt{26}$$