Solve x^2+5=131

$$x ^ { 2 } + 5 = 131$$

Solve for x

$$x=3\sqrt{14}\approx 11.22497216$$

$$x=-3\sqrt{14}\approx -11.22497216$$

Steps by Finding Square Root

Subtract 5 from both sides.

$$x^{2}=131-5$$

Subtract 5 from 131 to get 126.

$$x^{2}=126$$

Take the square root of both sides of the equation.

$$x=3\sqrt{14} x=-3\sqrt{14}$$

Steps Using the Quadratic Formula

Subtract 131 from both sides.

$$x^{2}+5-131=0$$

Subtract 131 from 5 to get -126.

$$x^{2}-126=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -126 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-126\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-126\right)}}{2}$$

Multiply -4 times -126.

$$x=\frac{0±\sqrt{504}}{2}$$

Take the square root of 504.

$$x=\frac{0±6\sqrt{14}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{14}}{2} when ± is plus.

$$x=3\sqrt{14}$$

Now solve the equation x=\frac{0±6\sqrt{14}}{2} when ± is minus.

$$x=-3\sqrt{14}$$

The equation is now solved.

$$x=3\sqrt{14} x=-3\sqrt{14}$$