Solve x^2+5=(x+5)^2

$$x ^ { 2 } + 5 = ( x + 5 ) ^ { 2 }$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+5\right)^{2}.

$$x^{2}+5=x^{2}+10x+25$$

Subtract x^{2} from both sides.

$$x^{2}+5-x^{2}=10x+25$$

Combine x^{2} and -x^{2} to get 0.

$$5=10x+25$$

Swap sides so that all variable terms are on the left hand side.

$$10x+25=5$$

Subtract 25 from both sides.

$$10x=5-25$$

Subtract 25 from 5 to get -20.

$$10x=-20$$

Divide both sides by 10.

$$x=\frac{-20}{10}$$

Divide -20 by 10 to get -2.

$$x=-2$$