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x\left(x+48\right)=0
Factor out x.
x=0 x=-48
To find equation solutions, solve x=0 and x+48=0.
x^{2}+48x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-48±\sqrt{48^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 48 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-48±48}{2}
Take the square root of 48^{2}.
x=\frac{0}{2}
Now solve the equation x=\frac{-48±48}{2} when ± is plus. Add -48 to 48.
x=0
Divide 0 by 2.
x=-\frac{96}{2}
Now solve the equation x=\frac{-48±48}{2} when ± is minus. Subtract 48 from -48.
x=-48
Divide -96 by 2.
x=0 x=-48
The equation is now solved.
x^{2}+48x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+48x+24^{2}=24^{2}
Divide 48, the coefficient of the x term, by 2 to get 24. Then add the square of 24 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+48x+576=576
Square 24.
\left(x+24\right)^{2}=576
Factor x^{2}+48x+576. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+24\right)^{2}}=\sqrt{576}
Take the square root of both sides of the equation.
x+24=24 x+24=-24
Simplify.
x=0 x=-48
Subtract 24 from both sides of the equation.