Solve for y
y=\frac{7-x^{2}}{4}
Solve for x (complex solution)
x=-\sqrt{7-4y}
x=\sqrt{7-4y}
Solve for x
x=\sqrt{7-4y}
x=-\sqrt{7-4y}\text{, }y\leq \frac{7}{4}
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4y-7=-x^{2}
Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.
4y=-x^{2}+7
Add 7 to both sides.
4y=7-x^{2}
The equation is in standard form.
\frac{4y}{4}=\frac{7-x^{2}}{4}
Divide both sides by 4.
y=\frac{7-x^{2}}{4}
Dividing by 4 undoes the multiplication by 4.
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