Solve x^2+4x-y+9=0

$$x ^ { 2 } + 4 x - y + 9 = 0$$

Solve for y

$$y=x^{2}+4x+9$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$4x-y+9=-x^{2}$$

Subtract 4x from both sides.

$$-y+9=-x^{2}-4x$$

Subtract 9 from both sides.

$$-y=-x^{2}-4x-9$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-x^{2}-4x-9}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-x^{2}-4x-9}{-1}$$

Divide -x^{2}-4x-9 by -1.

$$y=x^{2}+4x+9$$

Solve for x (complex solution)

$$x=\sqrt{y-5}-2$$

$$x=-\sqrt{y-5}-2$$

Solve for x

$$x=\sqrt{y-5}-2$$

$$x=-\sqrt{y-5}-2\text{, }y\geq 5$$