Solve x^2+34+5=0

$$x ^ { 2 } + 34 + 5 = 0$$

Solve for x (complex solution)

$$x=-\sqrt{39}i\approx -0-6.244997998i$$

$$x=\sqrt{39}i\approx 6.244997998i$$

Steps by Finding Square Root

Add 34 and 5 to get 39.

$$x^{2}+39=0$$

Subtract 39 from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-39$$

The equation is now solved.

$$x=\sqrt{39}i x=-\sqrt{39}i$$

Steps Using the Quadratic Formula

Add 34 and 5 to get 39.

$$x^{2}+39=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 39 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 39}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 39}}{2}$$

Multiply -4 times 39.

$$x=\frac{0±\sqrt{-156}}{2}$$

Take the square root of -156.

$$x=\frac{0±2\sqrt{39}i}{2}$$

Now solve the equation x=\frac{0±2\sqrt{39}i}{2} when ± is plus.

$$x=\sqrt{39}i$$

Now solve the equation x=\frac{0±2\sqrt{39}i}{2} when ± is minus.

$$x=-\sqrt{39}i$$

The equation is now solved.

$$x=\sqrt{39}i x=-\sqrt{39}i$$