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a+b=31 ab=-360
To solve the equation, factor x^{2}+31x-360 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
-1,360 -2,180 -3,120 -4,90 -5,72 -6,60 -8,45 -9,40 -10,36 -12,30 -15,24 -18,20
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -360.
-1+360=359 -2+180=178 -3+120=117 -4+90=86 -5+72=67 -6+60=54 -8+45=37 -9+40=31 -10+36=26 -12+30=18 -15+24=9 -18+20=2
Calculate the sum for each pair.
a=-9 b=40
The solution is the pair that gives sum 31.
\left(x-9\right)\left(x+40\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=9 x=-40
To find equation solutions, solve x-9=0 and x+40=0.
a+b=31 ab=1\left(-360\right)=-360
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-360. To find a and b, set up a system to be solved.
-1,360 -2,180 -3,120 -4,90 -5,72 -6,60 -8,45 -9,40 -10,36 -12,30 -15,24 -18,20
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -360.
-1+360=359 -2+180=178 -3+120=117 -4+90=86 -5+72=67 -6+60=54 -8+45=37 -9+40=31 -10+36=26 -12+30=18 -15+24=9 -18+20=2
Calculate the sum for each pair.
a=-9 b=40
The solution is the pair that gives sum 31.
\left(x^{2}-9x\right)+\left(40x-360\right)
Rewrite x^{2}+31x-360 as \left(x^{2}-9x\right)+\left(40x-360\right).
x\left(x-9\right)+40\left(x-9\right)
Factor out x in the first and 40 in the second group.
\left(x-9\right)\left(x+40\right)
Factor out common term x-9 by using distributive property.
x=9 x=-40
To find equation solutions, solve x-9=0 and x+40=0.
x^{2}+31x-360=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-31±\sqrt{31^{2}-4\left(-360\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 31 for b, and -360 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-31±\sqrt{961-4\left(-360\right)}}{2}
Square 31.
x=\frac{-31±\sqrt{961+1440}}{2}
Multiply -4 times -360.
x=\frac{-31±\sqrt{2401}}{2}
Add 961 to 1440.
x=\frac{-31±49}{2}
Take the square root of 2401.
x=\frac{18}{2}
Now solve the equation x=\frac{-31±49}{2} when ± is plus. Add -31 to 49.
x=9
Divide 18 by 2.
x=-\frac{80}{2}
Now solve the equation x=\frac{-31±49}{2} when ± is minus. Subtract 49 from -31.
x=-40
Divide -80 by 2.
x=9 x=-40
The equation is now solved.
x^{2}+31x-360=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+31x-360-\left(-360\right)=-\left(-360\right)
Add 360 to both sides of the equation.
x^{2}+31x=-\left(-360\right)
Subtracting -360 from itself leaves 0.
x^{2}+31x=360
Subtract -360 from 0.
x^{2}+31x+\left(\frac{31}{2}\right)^{2}=360+\left(\frac{31}{2}\right)^{2}
Divide 31, the coefficient of the x term, by 2 to get \frac{31}{2}. Then add the square of \frac{31}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+31x+\frac{961}{4}=360+\frac{961}{4}
Square \frac{31}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+31x+\frac{961}{4}=\frac{2401}{4}
Add 360 to \frac{961}{4}.
\left(x+\frac{31}{2}\right)^{2}=\frac{2401}{4}
Factor x^{2}+31x+\frac{961}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{31}{2}\right)^{2}}=\sqrt{\frac{2401}{4}}
Take the square root of both sides of the equation.
x+\frac{31}{2}=\frac{49}{2} x+\frac{31}{2}=-\frac{49}{2}
Simplify.
x=9 x=-40
Subtract \frac{31}{2} from both sides of the equation.
x ^ 2 +31x -360 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -31 rs = -360
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{31}{2} - u s = -\frac{31}{2} + u
Two numbers r and s sum up to -31 exactly when the average of the two numbers is \frac{1}{2}*-31 = -\frac{31}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{31}{2} - u) (-\frac{31}{2} + u) = -360
To solve for unknown quantity u, substitute these in the product equation rs = -360
\frac{961}{4} - u^2 = -360
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -360-\frac{961}{4} = -\frac{2401}{4}
Simplify the expression by subtracting \frac{961}{4} on both sides
u^2 = \frac{2401}{4} u = \pm\sqrt{\frac{2401}{4}} = \pm \frac{49}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{31}{2} - \frac{49}{2} = -40 s = -\frac{31}{2} + \frac{49}{2} = 9
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.