Solve for y
y=\frac{2z-x^{2}}{3}
Solve for x (complex solution)
x=-\sqrt{2z-3y}
x=\sqrt{2z-3y}
Solve for x
x=\sqrt{2z-3y}
x=-\sqrt{2z-3y}\text{, }y\leq \frac{2z}{3}
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3y-2z=-x^{2}
Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.
3y=-x^{2}+2z
Add 2z to both sides.
3y=2z-x^{2}
The equation is in standard form.
\frac{3y}{3}=\frac{2z-x^{2}}{3}
Divide both sides by 3.
y=\frac{2z-x^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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