Solve x^2+3y=12

$$x ^ { 2 } + 3 y = 12$$

Solve for y

$$y=-\frac{x^{2}}{3}+4$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$3y=12-x^{2}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{12-x^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{12-x^{2}}{3}$$

Divide 12-x^{2} by 3.

$$y=-\frac{x^{2}}{3}+4$$

Solve for x (complex solution)

$$x=-\sqrt{12-3y}$$

$$x=\sqrt{12-3y}$$

Solve for x

$$x=\sqrt{12-3y}$$

$$x=-\sqrt{12-3y}\text{, }y\leq 4$$