Solve x^2+3y+27=0

$$x ^ { 2 } + 3 y + 27 = 0$$

Solve for y

$$y=-\frac{x^{2}}{3}-9$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$3y+27=-x^{2}$$

Subtract 27 from both sides.

$$3y=-x^{2}-27$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-x^{2}-27}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-x^{2}-27}{3}$$

Divide -x^{2}-27 by 3.

$$y=-\frac{x^{2}}{3}-9$$

Solve for x (complex solution)

$$x=-\sqrt{-3y-27}$$

$$x=\sqrt{-3y-27}$$

Solve for x

$$x=\sqrt{-3y-27}$$

$$x=-\sqrt{-3y-27}\text{, }y\leq -9$$