Solve x^2+3x-y=7

$$x ^ { 2 } + 3 x - y = 7$$

Solve for y

$$y=x^{2}+3x-7$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$3x-y=7-x^{2}$$

Subtract 3x from both sides.

$$-y=7-x^{2}-3x$$

The equation is in standard form.

$$-y=7-3x-x^{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{7-3x-x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{7-3x-x^{2}}{-1}$$

Divide 7-x^{2}-3x by -1.

$$y=x^{2}+3x-7$$

Solve for x (complex solution)

$$x=\frac{\sqrt{4y+37}-3}{2}$$

$$x=\frac{-\sqrt{4y+37}-3}{2}$$

Solve for x

$$x=\frac{\sqrt{4y+37}-3}{2}$$

$$x=\frac{-\sqrt{4y+37}-3}{2}\text{, }y\geq -\frac{37}{4}$$