Solve x^2+3x+1=xi_{4}1+2x+x^2-2x+2/2x

$$x ^ { 2 } + 3 x + 1 = \xi _ { 4 } 1 + 2 x + x ^ { 2 } - 2 x + \frac { 2 } { 2 } x$$

Solve for x

$$x=\frac{\xi _{4}-1}{2}$$

Steps for Solving Linear Equation

Combine 2x and -2x to get 0.

$$x^{2}+3x+1=\xi _{4}\times 1+x^{2}+\frac{2}{2}x$$

Divide 2 by 2 to get 1.

$$x^{2}+3x+1=\xi _{4}\times 1+x^{2}+1x$$

Subtract x^{2} from both sides.

$$x^{2}+3x+1-x^{2}=\xi _{4}\times 1+1x$$

Combine x^{2} and -x^{2} to get 0.

$$3x+1=\xi _{4}\times 1+1x$$

Subtract 1x from both sides.

$$3x+1-x=\xi _{4}\times 1$$

Combine 3x and -x to get 2x.

$$2x+1=\xi _{4}\times 1$$

Subtract 1 from both sides.

$$2x=\xi _{4}\times 1-1$$

Reorder the terms.

$$2x=\xi _{4}-1$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\xi _{4}-1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\xi _{4}-1}{2}$$

Solve for ξ_4

$$\xi _{4}=2x+1$$

Solution Steps

Combine 2x and -2x to get 0.

$$x^{2}+3x+1=\xi _{4}\times 1+x^{2}+\frac{2}{2}x$$

Divide 2 by 2 to get 1.

$$x^{2}+3x+1=\xi _{4}\times 1+x^{2}+1x$$

Swap sides so that all variable terms are on the left hand side.

$$\xi _{4}\times 1+x^{2}+1x=x^{2}+3x+1$$

Subtract x^{2} from both sides.

$$\xi _{4}\times 1+1x=x^{2}+3x+1-x^{2}$$

Combine x^{2} and -x^{2} to get 0.

$$\xi _{4}\times 1+1x=3x+1$$

Subtract 1x from both sides.

$$\xi _{4}\times 1=3x+1-x$$

Combine 3x and -x to get 2x.

$$\xi _{4}\times 1=2x+1$$

Reorder the terms.

$$\xi _{4}=2x+1$$