Solve x^2+3^2=(9-x)^2

$$x ^ { 2 } + 3 ^ { 2 } = ( 9 - x ) ^ { 2 }$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$x^{2}+9=\left(9-x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(9-x\right)^{2}.

$$x^{2}+9=81-18x+x^{2}$$

Add 18x to both sides.

$$x^{2}+9+18x=81+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+9+18x-x^{2}=81$$

Combine x^{2} and -x^{2} to get 0.

$$9+18x=81$$

Subtract 9 from both sides.

$$18x=81-9$$

Subtract 9 from 81 to get 72.

$$18x=72$$

Divide both sides by 18.

$$x=\frac{72}{18}$$

Divide 72 by 18 to get 4.

$$x=4$$