Solve x^2+2y-5=0

$$x ^ { 2 } + 2 y - 5 = 0$$

Solve for y

$$y=\frac{5-x^{2}}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$2y-5=-x^{2}$$

Add 5 to both sides.

$$2y=-x^{2}+5$$

The equation is in standard form.

$$2y=5-x^{2}$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{5-x^{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{5-x^{2}}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{5-2y}$$

$$x=\sqrt{5-2y}$$

Solve for x

$$x=\sqrt{5-2y}$$

$$x=-\sqrt{5-2y}\text{, }y\leq \frac{5}{2}$$