Solve for y
y=-\frac{x}{2}-\frac{4}{x}
x\neq 0
Solve for x (complex solution)
x=\sqrt{y^{2}-8}-y
x=-\sqrt{y^{2}-8}-y
Solve for x
x=\sqrt{y^{2}-8}-y
x=-\sqrt{y^{2}-8}-y\text{, }|y|\geq 2\sqrt{2}
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2xy=-8-x^{2}
Subtract x^{2} from both sides.
2xy=-x^{2}-8
The equation is in standard form.
\frac{2xy}{2x}=\frac{-x^{2}-8}{2x}
Divide both sides by 2x.
y=\frac{-x^{2}-8}{2x}
Dividing by 2x undoes the multiplication by 2x.
y=-\frac{x}{2}-\frac{4}{x}
Divide -8-x^{2} by 2x.
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