Solve x^2+2x+1=3x-2

$$x ^ { 2 } + 2 x + 1 = 3 x - 2$$

Solve for x (complex solution)

$$x=\frac{1+\sqrt{11}i}{2}\approx 0.5+1.658312395i$$

$$x=\frac{-\sqrt{11}i+1}{2}\approx 0.5-1.658312395i$$

Steps Using the Quadratic Formula

Subtract 3x from both sides.

$$x^{2}+2x+1-3x=-2$$

Combine 2x and -3x to get -x.

$$x^{2}-x+1=-2$$

Add 2 to both sides.

$$x^{2}-x+1+2=0$$

Add 1 and 2 to get 3.

$$x^{2}-x+3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1-4\times 3}}{2}$$

Multiply -4 times 3.

$$x=\frac{-\left(-1\right)±\sqrt{1-12}}{2}$$

Add 1 to -12.

$$x=\frac{-\left(-1\right)±\sqrt{-11}}{2}$$

Take the square root of -11.

$$x=\frac{-\left(-1\right)±\sqrt{11}i}{2}$$

The opposite of -1 is 1.

$$x=\frac{1±\sqrt{11}i}{2}$$

Now solve the equation x=\frac{1±\sqrt{11}i}{2} when ± is plus. Add 1 to i\sqrt{11}.

$$x=\frac{1+\sqrt{11}i}{2}$$

Now solve the equation x=\frac{1±\sqrt{11}i}{2} when ± is minus. Subtract i\sqrt{11} from 1.

$$x=\frac{-\sqrt{11}i+1}{2}$$

The equation is now solved.

$$x=\frac{1+\sqrt{11}i}{2} x=\frac{-\sqrt{11}i+1}{2}$$

Steps for Completing the Square

Subtract 3x from both sides.

$$x^{2}+2x+1-3x=-2$$

Combine 2x and -3x to get -x.

$$x^{2}-x+1=-2$$

Subtract 1 from both sides.

$$x^{2}-x=-2-1$$

Subtract 1 from -2 to get -3.

$$x^{2}-x=-3$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-3+\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=-3+\frac{1}{4}$$

Add -3 to \frac{1}{4}.

$$x^{2}-x+\frac{1}{4}=-\frac{11}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=-\frac{11}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{11}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{\sqrt{11}i}{2} x-\frac{1}{2}=-\frac{\sqrt{11}i}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=\frac{1+\sqrt{11}i}{2} x=\frac{-\sqrt{11}i+1}{2}$$