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x^{2}+x-2
Multiply and combine like terms.
a+b=1 ab=1\left(-2\right)=-2
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-2. To find a and b, set up a system to be solved.
a=-1 b=2
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(x^{2}-x\right)+\left(2x-2\right)
Rewrite x^{2}+x-2 as \left(x^{2}-x\right)+\left(2x-2\right).
x\left(x-1\right)+2\left(x-1\right)
Factor out x in the first and 2 in the second group.
\left(x-1\right)\left(x+2\right)
Factor out common term x-1 by using distributive property.
x^{2}-2+x
Subtract 4 from 2 to get -2.