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x^{2}+10x-187\times 5=0
Multiply 2 and 5 to get 10.
x^{2}+10x-935=0
Multiply 187 and 5 to get 935.
x=\frac{-10±\sqrt{10^{2}-4\left(-935\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 10 for b, and -935 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\left(-935\right)}}{2}
Square 10.
x=\frac{-10±\sqrt{100+3740}}{2}
Multiply -4 times -935.
x=\frac{-10±\sqrt{3840}}{2}
Add 100 to 3740.
x=\frac{-10±16\sqrt{15}}{2}
Take the square root of 3840.
x=\frac{16\sqrt{15}-10}{2}
Now solve the equation x=\frac{-10±16\sqrt{15}}{2} when ± is plus. Add -10 to 16\sqrt{15}.
x=8\sqrt{15}-5
Divide -10+16\sqrt{15} by 2.
x=\frac{-16\sqrt{15}-10}{2}
Now solve the equation x=\frac{-10±16\sqrt{15}}{2} when ± is minus. Subtract 16\sqrt{15} from -10.
x=-8\sqrt{15}-5
Divide -10-16\sqrt{15} by 2.
x=8\sqrt{15}-5 x=-8\sqrt{15}-5
The equation is now solved.
x^{2}+10x-187\times 5=0
Multiply 2 and 5 to get 10.
x^{2}+10x-935=0
Multiply 187 and 5 to get 935.
x^{2}+10x=935
Add 935 to both sides. Anything plus zero gives itself.
x^{2}+10x+5^{2}=935+5^{2}
Divide 10, the coefficient of the x term, by 2 to get 5. Then add the square of 5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+10x+25=935+25
Square 5.
x^{2}+10x+25=960
Add 935 to 25.
\left(x+5\right)^{2}=960
Factor x^{2}+10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{960}
Take the square root of both sides of the equation.
x+5=8\sqrt{15} x+5=-8\sqrt{15}
Simplify.
x=8\sqrt{15}-5 x=-8\sqrt{15}-5
Subtract 5 from both sides of the equation.