Solve x^2+16y-2=-14x-x^2-99

$$x ^ { 2 } + 16 y - 2 = - 14 x - x ^ { 2 } - 99$$

Solve for y

$$y=-\frac{x^{2}}{8}-\frac{7x}{8}-\frac{97}{16}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$16y-2=-14x-x^{2}-99-x^{2}$$

Combine -x^{2} and -x^{2} to get -2x^{2}.

$$16y-2=-14x-2x^{2}-99$$

Add 2 to both sides.

$$16y=-14x-2x^{2}-99+2$$

Add -99 and 2 to get -97.

$$16y=-14x-2x^{2}-97$$

The equation is in standard form.

$$16y=-2x^{2}-14x-97$$

Divide both sides by 16.

$$\frac{16y}{16}=\frac{-2x^{2}-14x-97}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$y=\frac{-2x^{2}-14x-97}{16}$$

Divide -14x-2x^{2}-97 by 16.

$$y=-\frac{x^{2}}{8}-\frac{7x}{8}-\frac{97}{16}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{-32y-145}-7}{2}$$

$$x=\frac{-\sqrt{-32y-145}-7}{2}$$

Solve for x

$$x=\frac{\sqrt{-32y-145}-7}{2}$$

$$x=\frac{-\sqrt{-32y-145}-7}{2}\text{, }y\leq -\frac{145}{32}$$