Solve x^2+16x+71quady=2x^2

$$x ^ { 2 } + 16 x + 71 \quad y = 2 x ^ { 2 }$$

Solve for y

$$y=-\frac{x\left(16-x\right)}{71}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$16x+71y=2x^{2}-x^{2}$$

Combine 2x^{2} and -x^{2} to get x^{2}.

$$16x+71y=x^{2}$$

Subtract 16x from both sides.

$$71y=x^{2}-16x$$

Divide both sides by 71.

$$\frac{71y}{71}=\frac{x\left(x-16\right)}{71}$$

Dividing by 71 undoes the multiplication by 71.

$$y=\frac{x\left(x-16\right)}{71}$$

Solve for x (complex solution)

$$x=-\sqrt{71y+64}+8$$

$$x=\sqrt{71y+64}+8$$

Solve for x

$$x=-\sqrt{71y+64}+8$$

$$x=\sqrt{71y+64}+8\text{, }y\geq -\frac{64}{71}$$