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a+b=15 ab=-2700
To solve the equation, factor x^{2}+15x-2700 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
-1,2700 -2,1350 -3,900 -4,675 -5,540 -6,450 -9,300 -10,270 -12,225 -15,180 -18,150 -20,135 -25,108 -27,100 -30,90 -36,75 -45,60 -50,54
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -2700.
-1+2700=2699 -2+1350=1348 -3+900=897 -4+675=671 -5+540=535 -6+450=444 -9+300=291 -10+270=260 -12+225=213 -15+180=165 -18+150=132 -20+135=115 -25+108=83 -27+100=73 -30+90=60 -36+75=39 -45+60=15 -50+54=4
Calculate the sum for each pair.
a=-45 b=60
The solution is the pair that gives sum 15.
\left(x-45\right)\left(x+60\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=45 x=-60
To find equation solutions, solve x-45=0 and x+60=0.
a+b=15 ab=1\left(-2700\right)=-2700
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-2700. To find a and b, set up a system to be solved.
-1,2700 -2,1350 -3,900 -4,675 -5,540 -6,450 -9,300 -10,270 -12,225 -15,180 -18,150 -20,135 -25,108 -27,100 -30,90 -36,75 -45,60 -50,54
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -2700.
-1+2700=2699 -2+1350=1348 -3+900=897 -4+675=671 -5+540=535 -6+450=444 -9+300=291 -10+270=260 -12+225=213 -15+180=165 -18+150=132 -20+135=115 -25+108=83 -27+100=73 -30+90=60 -36+75=39 -45+60=15 -50+54=4
Calculate the sum for each pair.
a=-45 b=60
The solution is the pair that gives sum 15.
\left(x^{2}-45x\right)+\left(60x-2700\right)
Rewrite x^{2}+15x-2700 as \left(x^{2}-45x\right)+\left(60x-2700\right).
x\left(x-45\right)+60\left(x-45\right)
Factor out x in the first and 60 in the second group.
\left(x-45\right)\left(x+60\right)
Factor out common term x-45 by using distributive property.
x=45 x=-60
To find equation solutions, solve x-45=0 and x+60=0.
x^{2}+15x-2700=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-15±\sqrt{15^{2}-4\left(-2700\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 15 for b, and -2700 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-15±\sqrt{225-4\left(-2700\right)}}{2}
Square 15.
x=\frac{-15±\sqrt{225+10800}}{2}
Multiply -4 times -2700.
x=\frac{-15±\sqrt{11025}}{2}
Add 225 to 10800.
x=\frac{-15±105}{2}
Take the square root of 11025.
x=\frac{90}{2}
Now solve the equation x=\frac{-15±105}{2} when ± is plus. Add -15 to 105.
x=45
Divide 90 by 2.
x=-\frac{120}{2}
Now solve the equation x=\frac{-15±105}{2} when ± is minus. Subtract 105 from -15.
x=-60
Divide -120 by 2.
x=45 x=-60
The equation is now solved.
x^{2}+15x-2700=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+15x-2700-\left(-2700\right)=-\left(-2700\right)
Add 2700 to both sides of the equation.
x^{2}+15x=-\left(-2700\right)
Subtracting -2700 from itself leaves 0.
x^{2}+15x=2700
Subtract -2700 from 0.
x^{2}+15x+\left(\frac{15}{2}\right)^{2}=2700+\left(\frac{15}{2}\right)^{2}
Divide 15, the coefficient of the x term, by 2 to get \frac{15}{2}. Then add the square of \frac{15}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+15x+\frac{225}{4}=2700+\frac{225}{4}
Square \frac{15}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+15x+\frac{225}{4}=\frac{11025}{4}
Add 2700 to \frac{225}{4}.
\left(x+\frac{15}{2}\right)^{2}=\frac{11025}{4}
Factor x^{2}+15x+\frac{225}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{15}{2}\right)^{2}}=\sqrt{\frac{11025}{4}}
Take the square root of both sides of the equation.
x+\frac{15}{2}=\frac{105}{2} x+\frac{15}{2}=-\frac{105}{2}
Simplify.
x=45 x=-60
Subtract \frac{15}{2} from both sides of the equation.
x ^ 2 +15x -2700 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -15 rs = -2700
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{15}{2} - u s = -\frac{15}{2} + u
Two numbers r and s sum up to -15 exactly when the average of the two numbers is \frac{1}{2}*-15 = -\frac{15}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{15}{2} - u) (-\frac{15}{2} + u) = -2700
To solve for unknown quantity u, substitute these in the product equation rs = -2700
\frac{225}{4} - u^2 = -2700
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -2700-\frac{225}{4} = -\frac{11025}{4}
Simplify the expression by subtracting \frac{225}{4} on both sides
u^2 = \frac{11025}{4} u = \pm\sqrt{\frac{11025}{4}} = \pm \frac{105}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{15}{2} - \frac{105}{2} = -60 s = -\frac{15}{2} + \frac{105}{2} = 45
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.