Skip to main content
Solve for x (complex solution)
Tick mark Image
Graph

Similar Problems from Web Search

Share

x^{2}+15x+273=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-15±\sqrt{15^{2}-4\times 273}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 15 for b, and 273 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-15±\sqrt{225-4\times 273}}{2}
Square 15.
x=\frac{-15±\sqrt{225-1092}}{2}
Multiply -4 times 273.
x=\frac{-15±\sqrt{-867}}{2}
Add 225 to -1092.
x=\frac{-15±17\sqrt{3}i}{2}
Take the square root of -867.
x=\frac{-15+17\sqrt{3}i}{2}
Now solve the equation x=\frac{-15±17\sqrt{3}i}{2} when ± is plus. Add -15 to 17i\sqrt{3}.
x=\frac{-17\sqrt{3}i-15}{2}
Now solve the equation x=\frac{-15±17\sqrt{3}i}{2} when ± is minus. Subtract 17i\sqrt{3} from -15.
x=\frac{-15+17\sqrt{3}i}{2} x=\frac{-17\sqrt{3}i-15}{2}
The equation is now solved.
x^{2}+15x+273=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+15x+273-273=-273
Subtract 273 from both sides of the equation.
x^{2}+15x=-273
Subtracting 273 from itself leaves 0.
x^{2}+15x+\left(\frac{15}{2}\right)^{2}=-273+\left(\frac{15}{2}\right)^{2}
Divide 15, the coefficient of the x term, by 2 to get \frac{15}{2}. Then add the square of \frac{15}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+15x+\frac{225}{4}=-273+\frac{225}{4}
Square \frac{15}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+15x+\frac{225}{4}=-\frac{867}{4}
Add -273 to \frac{225}{4}.
\left(x+\frac{15}{2}\right)^{2}=-\frac{867}{4}
Factor x^{2}+15x+\frac{225}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{15}{2}\right)^{2}}=\sqrt{-\frac{867}{4}}
Take the square root of both sides of the equation.
x+\frac{15}{2}=\frac{17\sqrt{3}i}{2} x+\frac{15}{2}=-\frac{17\sqrt{3}i}{2}
Simplify.
x=\frac{-15+17\sqrt{3}i}{2} x=\frac{-17\sqrt{3}i-15}{2}
Subtract \frac{15}{2} from both sides of the equation.
x ^ 2 +15x +273 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -15 rs = 273
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{15}{2} - u s = -\frac{15}{2} + u
Two numbers r and s sum up to -15 exactly when the average of the two numbers is \frac{1}{2}*-15 = -\frac{15}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{15}{2} - u) (-\frac{15}{2} + u) = 273
To solve for unknown quantity u, substitute these in the product equation rs = 273
\frac{225}{4} - u^2 = 273
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 273-\frac{225}{4} = \frac{867}{4}
Simplify the expression by subtracting \frac{225}{4} on both sides
u^2 = -\frac{867}{4} u = \pm\sqrt{-\frac{867}{4}} = \pm \frac{\sqrt{867}}{2}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{15}{2} - \frac{\sqrt{867}}{2}i = -7.500 - 14.722i s = -\frac{15}{2} + \frac{\sqrt{867}}{2}i = -7.500 + 14.722i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.