Solve x^2+13x+42=(x+6)(x+1)

$$x ^ { 2 } + 13 x + 42 = ( x + 6 ) ( x + 1 )$$

Solve for x

$$x=-6$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+6 by x+1 and combine like terms.

$$x^{2}+13x+42=x^{2}+7x+6$$

Subtract x^{2} from both sides.

$$x^{2}+13x+42-x^{2}=7x+6$$

Combine x^{2} and -x^{2} to get 0.

$$13x+42=7x+6$$

Subtract 7x from both sides.

$$13x+42-7x=6$$

Combine 13x and -7x to get 6x.

$$6x+42=6$$

Subtract 42 from both sides.

$$6x=6-42$$

Subtract 42 from 6 to get -36.

$$6x=-36$$

Divide both sides by 6.

$$x=\frac{-36}{6}$$

Divide -36 by 6 to get -6.

$$x=-6$$