Solve x^2+12500^2=(14430.87)^2

$$x ^ { 2 } + 12500 ^ { 2 } = ( 14430.87 ) ^ { 2 }$$

Solve for x

$$x = \frac{\sqrt{520000089569}}{100} \approx 7211.103171977$$

$$x = -\frac{\sqrt{520000089569}}{100} \approx -7211.103171977$$

Steps by Finding Square Root

Calculate 12500 to the power of 2 and get 156250000.

$$x^{2}[phone]=14430.87^{2}$$

Calculate 14430.87 to the power of 2 and get 208250008.9569.

$$x^{2}[phone]=208250008.9569$$

Subtract 156250000 from both sides.

$$x^{2}=208250008.9569-156250000$$

Subtract 156250000 from 208250008.9569 to get 52000008.9569.

$$x^{2}=52000008.9569$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{520000089569}}{100} x=-\frac{\sqrt{520000089569}}{100}$$

Steps Using the Quadratic Formula

Calculate 12500 to the power of 2 and get 156250000.

$$x^{2}[phone]=14430.87^{2}$$

Calculate 14430.87 to the power of 2 and get 208250008.9569.

$$x^{2}[phone]=208250008.9569$$

Subtract 208250008.9569 from both sides.

$$x^{2}[phone]-208250008.9569=0$$

Subtract 208250008.9569 from 156250000 to get -52000008.9569.

$$x^{2}-52000008.9569=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -52000008.9569 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-52000008.9569\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-52000008.9569\right)}}{2}$$

Multiply -4 times -52000008.9569.

$$x=\frac{0±\sqrt{208000035.8276}}{2}$$

Take the square root of 208000035.8276.

$$x=\frac{0±\frac{\sqrt{520000089569}}{50}}{2}$$

Now solve the equation x=\frac{0±\frac{\sqrt{520000089569}}{50}}{2} when ± is plus.

$$x=\frac{\sqrt{520000089569}}{100}$$

Now solve the equation x=\frac{0±\frac{\sqrt{520000089569}}{50}}{2} when ± is minus.

$$x=-\frac{\sqrt{520000089569}}{100}$$

The equation is now solved.

$$x=\frac{\sqrt{520000089569}}{100} x=-\frac{\sqrt{520000089569}}{100}$$