Solve x^2+12-6c=0

$$x ^ { 2 } + 12 - 6 c = 0$$

Solve for c

$$c=\frac{x^{2}+12}{6}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$12-6c=-x^{2}$$

Subtract 12 from both sides.

$$-6c=-x^{2}-12$$

Divide both sides by -6.

$$\frac{-6c}{-6}=\frac{-x^{2}-12}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$c=\frac{-x^{2}-12}{-6}$$

Divide -x^{2}-12 by -6.

$$c=\frac{x^{2}}{6}+2$$

Solve for x (complex solution)

$$x=-\sqrt{6\left(c-2\right)}$$

$$x=\sqrt{6\left(c-2\right)}$$

Solve for x

$$x=\sqrt{6\left(c-2\right)}$$

$$x=-\sqrt{6\left(c-2\right)}\text{, }c\geq 2$$