Solve x^2+12^2=(17-x)^2

$$x ^ { 2 } + 12 ^ { 2 } = ( 17 - x ) ^ { 2 }$$

Solve for x

$$x = \frac{145}{34} = 4\frac{9}{34} \approx 4.264705882$$

Steps for Solving Linear Equation

Calculate 12 to the power of 2 and get 144.

$$x^{2}+144=\left(17-x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(17-x\right)^{2}.

$$x^{2}+144=289-34x+x^{2}$$

Add 34x to both sides.

$$x^{2}+144+34x=289+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+144+34x-x^{2}=289$$

Combine x^{2} and -x^{2} to get 0.

$$144+34x=289$$

Subtract 144 from both sides.

$$34x=289-144$$

Subtract 144 from 289 to get 145.

$$34x=145$$

Divide both sides by 34.

$$x=\frac{145}{34}$$