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x^{2}+80x-5\times 40=0
Multiply 1 and 80 to get 80.
x^{2}+80x-200=0
Multiply 5 and 40 to get 200.
x=\frac{-80±\sqrt{80^{2}-4\left(-200\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 80 for b, and -200 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-80±\sqrt{6400-4\left(-200\right)}}{2}
Square 80.
x=\frac{-80±\sqrt{6400+800}}{2}
Multiply -4 times -200.
x=\frac{-80±\sqrt{7200}}{2}
Add 6400 to 800.
x=\frac{-80±60\sqrt{2}}{2}
Take the square root of 7200.
x=\frac{60\sqrt{2}-80}{2}
Now solve the equation x=\frac{-80±60\sqrt{2}}{2} when ± is plus. Add -80 to 60\sqrt{2}.
x=30\sqrt{2}-40
Divide -80+60\sqrt{2} by 2.
x=\frac{-60\sqrt{2}-80}{2}
Now solve the equation x=\frac{-80±60\sqrt{2}}{2} when ± is minus. Subtract 60\sqrt{2} from -80.
x=-30\sqrt{2}-40
Divide -80-60\sqrt{2} by 2.
x=30\sqrt{2}-40 x=-30\sqrt{2}-40
The equation is now solved.
x^{2}+80x-5\times 40=0
Multiply 1 and 80 to get 80.
x^{2}+80x-200=0
Multiply 5 and 40 to get 200.
x^{2}+80x=200
Add 200 to both sides. Anything plus zero gives itself.
x^{2}+80x+40^{2}=200+40^{2}
Divide 80, the coefficient of the x term, by 2 to get 40. Then add the square of 40 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+80x+1600=200+1600
Square 40.
x^{2}+80x+1600=1800
Add 200 to 1600.
\left(x+40\right)^{2}=1800
Factor x^{2}+80x+1600. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+40\right)^{2}}=\sqrt{1800}
Take the square root of both sides of the equation.
x+40=30\sqrt{2} x+40=-30\sqrt{2}
Simplify.
x=30\sqrt{2}-40 x=-30\sqrt{2}-40
Subtract 40 from both sides of the equation.