Solve x^2+036x^2=225

$$x ^ { 2 } + 036 x ^ { 2 } = 225$$

Solve for x

$$x=15$$

$$x=-15$$

Steps Using Difference of Squares

Multiply 0 and 36 to get 0.

$$x^{2}+0x^{2}=225$$

Anything times zero gives zero.

$$x^{2}+0=225$$

Anything plus zero gives itself.

$$x^{2}=225$$

Subtract 225 from both sides.

$$x^{2}-225=0$$

Consider x^{2}-225. Rewrite x^{2}-225 as x^{2}-15^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-15\right)\left(x+15\right)=0$$

To find equation solutions, solve x-15=0 and x+15=0.

$$x=15 x=-15$$

Steps by Finding Square Root

Multiply 0 and 36 to get 0.

$$x^{2}+0x^{2}=225$$

Anything times zero gives zero.

$$x^{2}+0=225$$

Anything plus zero gives itself.

$$x^{2}=225$$

Take the square root of both sides of the equation.

$$x=15 x=-15$$

Steps Using the Quadratic Formula

Multiply 0 and 36 to get 0.

$$x^{2}+0x^{2}=225$$

Anything times zero gives zero.

$$x^{2}+0=225$$

Anything plus zero gives itself.

$$x^{2}=225$$

Subtract 225 from both sides.

$$x^{2}-225=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -225 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-225\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-225\right)}}{2}$$

Multiply -4 times -225.

$$x=\frac{0±\sqrt{900}}{2}$$

Take the square root of 900.

$$x=\frac{0±30}{2}$$

Now solve the equation x=\frac{0±30}{2} when ± is plus. Divide 30 by 2.

$$x=15$$

Now solve the equation x=\frac{0±30}{2} when ± is minus. Divide -30 by 2.

$$x=-15$$

The equation is now solved.

$$x=15 x=-15$$