Solve x^2+0x+4

$$x ^ { 2 } + 0 x + 4$$

Evaluate

$$x^{2}+4$$

Solution Steps

Anything times zero gives zero.

$$x^{2}+0+4$$

Add 0 and 4 to get 4.

$$x^{2}+4$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

$$x ^ 2 +0x +4 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = 0 rs = 4$$

Two numbers r and s sum up to 0 exactly when the average of the two numbers is \frac{1}{2}*0 = 0. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = 0 - u s = 0 + u$$

To solve for unknown quantity u, substitute these in the product equation rs = 4

$$(0 - u) (0 + u) = 4$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$0 - u^2 = 4$$

Simplify the expression by subtracting 0 on both sides

$$-u^2 = 4-0 = 4$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = -4 u = \pm\sqrt{-4} = \pm 2i$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =0 - 2i s = 0 + 2i$$

Differentiate w.r.t. x

$$2x$$

Steps Using Derivative Rule for Sum

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+0+4)$$

Add 0 and 4 to get 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2x^{2-1}$$

Subtract 1 from 2.

$$2x^{1}$$

For any term t, t^{1}=t.

$$2x$$