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Solve for x (complex solution)
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2x^{2}+x^{4}=6
Multiply both sides of the equation by 2.
2x^{2}+x^{4}-6=0
Subtract 6 from both sides.
t^{2}+2t-6=0
Substitute t for x^{2}.
t=\frac{-2±\sqrt{2^{2}-4\times 1\left(-6\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 2 for b, and -6 for c in the quadratic formula.
t=\frac{-2±2\sqrt{7}}{2}
Do the calculations.
t=\sqrt{7}-1 t=-\sqrt{7}-1
Solve the equation t=\frac{-2±2\sqrt{7}}{2} when ± is plus and when ± is minus.
x=-\sqrt{\sqrt{7}-1} x=\sqrt{\sqrt{7}-1} x=-i\sqrt{\sqrt{7}+1} x=i\sqrt{\sqrt{7}+1}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
2x^{2}+x^{4}=6
Multiply both sides of the equation by 2.
2x^{2}+x^{4}-6=0
Subtract 6 from both sides.
t^{2}+2t-6=0
Substitute t for x^{2}.
t=\frac{-2±\sqrt{2^{2}-4\times 1\left(-6\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 2 for b, and -6 for c in the quadratic formula.
t=\frac{-2±2\sqrt{7}}{2}
Do the calculations.
t=\sqrt{7}-1 t=-\sqrt{7}-1
Solve the equation t=\frac{-2±2\sqrt{7}}{2} when ± is plus and when ± is minus.
x=\sqrt{\sqrt{7}-1} x=-\sqrt{\sqrt{7}-1}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.