Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

11x^{2}+\frac{4}{5}\times 7\times \frac{x}{2}=33
Multiply both sides of the equation by 11.
11x^{2}+\frac{28}{5}\times \frac{x}{2}=33
Multiply \frac{4}{5} and 7 to get \frac{28}{5}.
11x^{2}+\frac{28x}{5\times 2}=33
Multiply \frac{28}{5} times \frac{x}{2} by multiplying numerator times numerator and denominator times denominator.
11x^{2}+\frac{14x}{5}=33
Cancel out 2 in both numerator and denominator.
11x^{2}+\frac{14x}{5}-33=0
Subtract 33 from both sides.
55x^{2}+14x-165=0
Multiply both sides of the equation by 5.
x=\frac{-14±\sqrt{14^{2}-4\times 55\left(-165\right)}}{2\times 55}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 55 for a, 14 for b, and -165 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-14±\sqrt{196-4\times 55\left(-165\right)}}{2\times 55}
Square 14.
x=\frac{-14±\sqrt{196-220\left(-165\right)}}{2\times 55}
Multiply -4 times 55.
x=\frac{-14±\sqrt{196+36300}}{2\times 55}
Multiply -220 times -165.
x=\frac{-14±\sqrt{36496}}{2\times 55}
Add 196 to 36300.
x=\frac{-14±4\sqrt{2281}}{2\times 55}
Take the square root of 36496.
x=\frac{-14±4\sqrt{2281}}{110}
Multiply 2 times 55.
x=\frac{4\sqrt{2281}-14}{110}
Now solve the equation x=\frac{-14±4\sqrt{2281}}{110} when ± is plus. Add -14 to 4\sqrt{2281}.
x=\frac{2\sqrt{2281}-7}{55}
Divide -14+4\sqrt{2281} by 110.
x=\frac{-4\sqrt{2281}-14}{110}
Now solve the equation x=\frac{-14±4\sqrt{2281}}{110} when ± is minus. Subtract 4\sqrt{2281} from -14.
x=\frac{-2\sqrt{2281}-7}{55}
Divide -14-4\sqrt{2281} by 110.
x=\frac{2\sqrt{2281}-7}{55} x=\frac{-2\sqrt{2281}-7}{55}
The equation is now solved.
11x^{2}+\frac{4}{5}\times 7\times \frac{x}{2}=33
Multiply both sides of the equation by 11.
11x^{2}+\frac{28}{5}\times \frac{x}{2}=33
Multiply \frac{4}{5} and 7 to get \frac{28}{5}.
11x^{2}+\frac{28x}{5\times 2}=33
Multiply \frac{28}{5} times \frac{x}{2} by multiplying numerator times numerator and denominator times denominator.
11x^{2}+\frac{14x}{5}=33
Cancel out 2 in both numerator and denominator.
55x^{2}+14x=165
Multiply both sides of the equation by 5.
\frac{55x^{2}+14x}{55}=\frac{165}{55}
Divide both sides by 55.
x^{2}+\frac{14}{55}x=\frac{165}{55}
Dividing by 55 undoes the multiplication by 55.
x^{2}+\frac{14}{55}x=3
Divide 165 by 55.
x^{2}+\frac{14}{55}x+\left(\frac{7}{55}\right)^{2}=3+\left(\frac{7}{55}\right)^{2}
Divide \frac{14}{55}, the coefficient of the x term, by 2 to get \frac{7}{55}. Then add the square of \frac{7}{55} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{14}{55}x+\frac{49}{3025}=3+\frac{49}{3025}
Square \frac{7}{55} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{14}{55}x+\frac{49}{3025}=\frac{9124}{3025}
Add 3 to \frac{49}{3025}.
\left(x+\frac{7}{55}\right)^{2}=\frac{9124}{3025}
Factor x^{2}+\frac{14}{55}x+\frac{49}{3025}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{7}{55}\right)^{2}}=\sqrt{\frac{9124}{3025}}
Take the square root of both sides of the equation.
x+\frac{7}{55}=\frac{2\sqrt{2281}}{55} x+\frac{7}{55}=-\frac{2\sqrt{2281}}{55}
Simplify.
x=\frac{2\sqrt{2281}-7}{55} x=\frac{-2\sqrt{2281}-7}{55}
Subtract \frac{7}{55} from both sides of the equation.