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x^{2}+\frac{7}{3}=6
Add \frac{1}{3} and 2 to get \frac{7}{3}.
x^{2}=6-\frac{7}{3}
Subtract \frac{7}{3} from both sides.
x^{2}=\frac{11}{3}
Subtract \frac{7}{3} from 6 to get \frac{11}{3}.
x=\frac{\sqrt{33}}{3} x=-\frac{\sqrt{33}}{3}
Take the square root of both sides of the equation.
x^{2}+\frac{7}{3}=6
Add \frac{1}{3} and 2 to get \frac{7}{3}.
x^{2}+\frac{7}{3}-6=0
Subtract 6 from both sides.
x^{2}-\frac{11}{3}=0
Subtract 6 from \frac{7}{3} to get -\frac{11}{3}.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{11}{3}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{11}{3} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{11}{3}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{44}{3}}}{2}
Multiply -4 times -\frac{11}{3}.
x=\frac{0±\frac{2\sqrt{33}}{3}}{2}
Take the square root of \frac{44}{3}.
x=\frac{\sqrt{33}}{3}
Now solve the equation x=\frac{0±\frac{2\sqrt{33}}{3}}{2} when ± is plus.
x=-\frac{\sqrt{33}}{3}
Now solve the equation x=\frac{0±\frac{2\sqrt{33}}{3}}{2} when ± is minus.
x=\frac{\sqrt{33}}{3} x=-\frac{\sqrt{33}}{3}
The equation is now solved.