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\frac{18x^{2}+9x+1}{18}
Factor out \frac{1}{18}.
a+b=9 ab=18\times 1=18
Consider 18x^{2}+9x+1. Factor the expression by grouping. First, the expression needs to be rewritten as 18x^{2}+ax+bx+1. To find a and b, set up a system to be solved.
1,18 2,9 3,6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 18.
1+18=19 2+9=11 3+6=9
Calculate the sum for each pair.
a=3 b=6
The solution is the pair that gives sum 9.
\left(18x^{2}+3x\right)+\left(6x+1\right)
Rewrite 18x^{2}+9x+1 as \left(18x^{2}+3x\right)+\left(6x+1\right).
3x\left(6x+1\right)+6x+1
Factor out 3x in 18x^{2}+3x.
\left(6x+1\right)\left(3x+1\right)
Factor out common term 6x+1 by using distributive property.
\frac{\left(6x+1\right)\left(3x+1\right)}{18}
Rewrite the complete factored expression.